3.1.62 \(\int \frac {(a+b x)^2}{x^7} \, dx\)

Optimal. Leaf size=30 \[ -\frac {a^2}{6 x^6}-\frac {2 a b}{5 x^5}-\frac {b^2}{4 x^4} \]

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Rubi [A]  time = 0.01, antiderivative size = 30, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {43} \begin {gather*} -\frac {a^2}{6 x^6}-\frac {2 a b}{5 x^5}-\frac {b^2}{4 x^4} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(a + b*x)^2/x^7,x]

[Out]

-a^2/(6*x^6) - (2*a*b)/(5*x^5) - b^2/(4*x^4)

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rubi steps

\begin {align*} \int \frac {(a+b x)^2}{x^7} \, dx &=\int \left (\frac {a^2}{x^7}+\frac {2 a b}{x^6}+\frac {b^2}{x^5}\right ) \, dx\\ &=-\frac {a^2}{6 x^6}-\frac {2 a b}{5 x^5}-\frac {b^2}{4 x^4}\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 30, normalized size = 1.00 \begin {gather*} -\frac {a^2}{6 x^6}-\frac {2 a b}{5 x^5}-\frac {b^2}{4 x^4} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(a + b*x)^2/x^7,x]

[Out]

-1/6*a^2/x^6 - (2*a*b)/(5*x^5) - b^2/(4*x^4)

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IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {(a+b x)^2}{x^7} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[(a + b*x)^2/x^7,x]

[Out]

IntegrateAlgebraic[(a + b*x)^2/x^7, x]

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fricas [A]  time = 0.72, size = 24, normalized size = 0.80 \begin {gather*} -\frac {15 \, b^{2} x^{2} + 24 \, a b x + 10 \, a^{2}}{60 \, x^{6}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^2/x^7,x, algorithm="fricas")

[Out]

-1/60*(15*b^2*x^2 + 24*a*b*x + 10*a^2)/x^6

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giac [A]  time = 1.07, size = 24, normalized size = 0.80 \begin {gather*} -\frac {15 \, b^{2} x^{2} + 24 \, a b x + 10 \, a^{2}}{60 \, x^{6}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^2/x^7,x, algorithm="giac")

[Out]

-1/60*(15*b^2*x^2 + 24*a*b*x + 10*a^2)/x^6

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maple [A]  time = 0.00, size = 25, normalized size = 0.83 \begin {gather*} -\frac {b^{2}}{4 x^{4}}-\frac {2 a b}{5 x^{5}}-\frac {a^{2}}{6 x^{6}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x+a)^2/x^7,x)

[Out]

-1/6*a^2/x^6-2/5*a*b/x^5-1/4*b^2/x^4

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maxima [A]  time = 1.35, size = 24, normalized size = 0.80 \begin {gather*} -\frac {15 \, b^{2} x^{2} + 24 \, a b x + 10 \, a^{2}}{60 \, x^{6}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^2/x^7,x, algorithm="maxima")

[Out]

-1/60*(15*b^2*x^2 + 24*a*b*x + 10*a^2)/x^6

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mupad [B]  time = 0.03, size = 24, normalized size = 0.80 \begin {gather*} -\frac {\frac {a^2}{6}+\frac {2\,a\,b\,x}{5}+\frac {b^2\,x^2}{4}}{x^6} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*x)^2/x^7,x)

[Out]

-(a^2/6 + (b^2*x^2)/4 + (2*a*b*x)/5)/x^6

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sympy [A]  time = 0.20, size = 26, normalized size = 0.87 \begin {gather*} \frac {- 10 a^{2} - 24 a b x - 15 b^{2} x^{2}}{60 x^{6}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)**2/x**7,x)

[Out]

(-10*a**2 - 24*a*b*x - 15*b**2*x**2)/(60*x**6)

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